ln 3 − 2 ln(8 + 4) write each expression as a single logarithm with a coefficient of 1?
Contract the expressions. That is, use the properties of logarithms to write each expression as a single logarithm with a coefficient of 1
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Hi,
ln 3 − 2 ln(8 + 4) =
ln 3 − 2 ln(12) =
ln 3 − ln(12)² =
ln 3 − ln144 =
. . .3
ln ------ =
. 144
. . .1
ln ------ <==ANSWER
. . 48
I hope that helps!! :-)
ln(3) -2ln(8+4)= ln(3) -2ln(12) =ln(3) -ln(12^2)= ln(3) -ln(144)
=ln(3/144)= ln(1/48)
The coefficient is now 1
Ln 3 − 2 ln(8 + 4)
=Ln 3 − ln(12)^2
= ln(3/144)
= ln(1/48)
= ln 1 - ln 48
= 0 -ln48
= - ln(48) ...................Ans
ln(3) – 2ln(12) = ln(3) – ln(144) = ln(3/144) = ln(1/48)