The sum is a Riemann sum for e^x over the interval [0,1], so
lim(n -> ∞) ∑(j = 1,n) (1/n) e^(j/n) = ∫[0,1] e^x dx = e - 1.
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The sum is a Riemann sum for e^x over the interval [0,1], so
lim(n -> ∞) ∑(j = 1,n) (1/n) e^(j/n) = ∫[0,1] e^x dx = e - 1.