in triangle ABC, a = 15 cm, c = 9 cm and angle B = 120°. the value of b (length of side AC) is?
i don't know what to do. i think there is a rule where if you know an angle and two corresponding sides, then you can find anything in the triangle but i don't know. can someone help?
Answers & Comments
Verified answer
Law of Cosines
c^2 = a^2 + b^2 - 2ab*cos(C)
b^2 = a^2 + c^2 - 2ac*cos(B)
a^2 = b^2 + c^2 - 2bc*cos(A)
The method is called the law of cosines:
C^2 = A^2 + B^2 - 2AB cosine of the angle between A and B
the pythagrian theorum is a special case where the angle is 90 degrees so the cosine is 0.
for the purpose of this C is the unknown side.
C^2 = (15^2) + (9^2) - 2(15)(9) cosine 120 degrees.
C^2 = 225 + 81 - 270( -.5)
( angle greater than 90 degees has a - cosine)
C^2 = 225 +81 + 135 = 441
C= 21Cm
Law of Cosines
AC=b
b^2=a^2+c^2-2ac cos(B)
b^2=15^2+9^2-2(15)(9) cos(120)
b^2=225+81-270cos(120)
b^2=306-27(-0.5)
=306+13.5
=219.5
AC=b=sqrt(319.5)=17.8745 cm
You may round it to the desired number of decimals.
use cosine laws
here...
b^2 = a^2 + c^2 - 2.a.c.cos B
just subst the given value.
thx