Point A is at a potential of +320 V, and point B is at a potential of -190 V. An α-particle is a helium nucleus that contains two protons...?
Point A is at a potential of +320 V, and point B is at a potential of -190 V. An α-particle is a helium nucleus that contains two protons and two neutrons; the neutrons are electrically neutral. An α-particle starts from rest at A and accelerates toward B. When the α-particle arrives at B, what kinetic energy (in electron volts) does it have?
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We know that volts are Joules/coulomb and the Vab = 510V with the E field pointing from A to B
Positively charged particles will experience force towards B. At B it s potential energy decrease = kinetic energy increase. 510V = 510J/C * 2*1.602e-19C = 1.63e-16 J = ½mV²
V² = 2*1.63e-16/6.695e-27 = (220,945m/s)² or about 221,000m/s <-------