A block with mass m = 21.4 kg slides down an inclined plane of slope angle 37.2 ° with a constant velocity. It?
A block with mass m = 21.4 kg slides down an inclined plane of slope angle 37.2 ° with a constant velocity. It is then projected up the same plane with an initial speed 1.70 m/s. How far up the incline will the block move before coming to rest?
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All of the energy that is kinetic at the bottom of the ramp must be transformed into gravitational potential energy (because the block comes to rest).
So:
(1/2)*m*v^2 = mgy
(1/2)*v^2 = gy
(1/2)*(1.7)^2 = 9.8*y
Isolate for y to find:
y = 0.147m
So the ball reaches a height of 0.147m - now simply use the Pythagorean theorem to find the distance along the ramp that this is.