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Zoe Levin
@Zoe Levin
May 2021
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If the heat of fusion of water is 80 cal/g, the amount of heat energy required to change 15.0g of ice at 0°C to 15.0g of water at 0°C is?
Science & Mathematics
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Chemistry
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derfram
15 g * 80 cal/g = 120 cal
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Answers & Comments
15 g * 80 cal/g = 120 cal