Verified answer

How many mL .....

Conservation of energy..... q=mcΔT ..... q(water) = 4.18 J/gC ..... D= 1.00g/mL

heat lost by hot water = -heat gained by cold water

mcΔT(hot) = -mcΔT(cold)

(75g)(4.18J/gC)(19 - 35)C = -x(4.18J/gC)(19-10)C

-5016 = -37.62x

x = 133g ... of water at 10.0C .... is the same as 133 mL of water