H = m c ΔT
89.6 J = (20.0 g) × c × (40.0 - 30.0)°C
Specific heat of iron, c = 89.6 / [20.0 × (40.0 - 30.0)] J/(g°C) = 0.448 J/(g°C)
The equation:
Heat energy = mass * specific heat * change in temp
89.6 = 20.0*Spec heat *(40.0-30.0)
Specific heat = 89.6/( 20.0*10.0)
Specific heat = 0.448J/g.°C
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Answers & Comments
H = m c ΔT
89.6 J = (20.0 g) × c × (40.0 - 30.0)°C
Specific heat of iron, c = 89.6 / [20.0 × (40.0 - 30.0)] J/(g°C) = 0.448 J/(g°C)
The equation:
Heat energy = mass * specific heat * change in temp
89.6 = 20.0*Spec heat *(40.0-30.0)
Specific heat = 89.6/( 20.0*10.0)
Specific heat = 0.448J/g.°C