A 800 two-stage rocket is traveling at a speed of 5.55×103 with respect to Earth when a pre-designed explosion?
A 800kg two-stage rocket is traveling at a speed of 5.55×10^3 m/s with respect to Earth when a pre-designed explosion separates the rocket into two sections of equal mass that then move at a speed of 3.00×10^3 m/s relative to each other along the original line of motion.
What is the speed of each section (relative to Earth) after the explosion?
Enter your answers numerically separated by a comma.
v1, v2=_____m/s
How much energy was supplied by the explosion? [Hint: What is the change in KE as a result of the explosion?]
E=_____J
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Since their momentum relative to each other must stay at zero and since each has the same mass...the speed of each ( relative to each other ) must be the same....1500 m/s
So vi is 7.05 m/s while vii is 4.05 m/s
Original KE = 1/2 . 800 . 5550^2
Final KE = 1/2 . 400 . 7050^2 + 1/2 . 400 . 4050^2