If Kc= 1.8 x 10^-6 for the reaction 2NO(g) + 0₂(g)= 2NO₂ (g) at 457 K? determine the value of Kp for the react?
The way that I did it:
kp= Kc(RT)^-1 = 1.8 x 10^-6 x (0.0821 x 457) ^ -1 and got 4.79 x 10 ^-8; however, the actual answer is kp = 4.6 x 10^3...how did they get that? Can someone please help me?
More Questions From This User See All
Answers & Comments
Verified answer
i think your answer is correct