if a/4 sin^2(15°) + a/4 cos^2(15°) = 8, the value of a is?
can someone help me? i don't even know how to start on solving this problem. i'm sure you have to use those trigonometry identities, but i don't know. can someone explain this?
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taking common of
a/4[sin^2(15)+cos^2(15)]=8
since sin^2(15)+cos^2(15)=1
a/4=8
a=32
Group it: .25a[sin^2(15°)+cos^2(15°)]
Since sin^2(x)+cos^2(x)=1 (trig identity), you have .25a=8. Multiplying by 4, a=32.
a/4[sin^2(15)+ cos^2(15)]=8
a/4[1]=8
a=32
bec
sin^2(thita)+cos ^2(thita)=1