If you subtract 5/17 from both sides of the equation 4Î/6Î + 5/17 = 1, you get:
4Î/6Î = 12/17
You could at this point try 0 through 9 for the possible digits represented by Î. If you wanted to do it algebraically, I'd prefer to call it X if you don't mind. The two digit number 4X means 40 + X, right? And the two digit number 6X means 60 + X. So that proportion really is:
You had the question all figured out. If you have no other method what you could do is just try the digits from 1 to 9 to see what happens. For example try 3
43/63. 43 is a prime number. So that is the wrong number: it will not reduce to 12/17.
Answers & Comments
Verified answer
Probably 8
The best clue is the denominators. What multiple of 17 is sixty-something? That'd be 68. Let's test
48 / 68 + 5/17 =>
12/17 + 5/17 =>
17/17
If you subtract 5/17 from both sides of the equation 4Î/6Î + 5/17 = 1, you get:
4Î/6Î = 12/17
You could at this point try 0 through 9 for the possible digits represented by Î. If you wanted to do it algebraically, I'd prefer to call it X if you don't mind. The two digit number 4X means 40 + X, right? And the two digit number 6X means 60 + X. So that proportion really is:
(40+X) / (60+X) = 12/17
Cross multiply
17(40+X) = 12(60+X)
680 + 17X = 720 + 12X
5X = 40
X = 8
Therefore, Î is 8
48/68 when this is divided by 4 you get 12/17
You had the question all figured out. If you have no other method what you could do is just try the digits from 1 to 9 to see what happens. For example try 3
43/63. 43 is a prime number. So that is the wrong number: it will not reduce to 12/17.
If you are in higher standard you can use Kathleen K answer
for lower standards
4Î ....1....5
----- = -- – -----
6Î ,,,,1 .. 17
=
4Î ....12
----- = ----
6Î ,,,, 17
find multiple of 12 and 17 having 8 in unit plaxe.
12 Ã 4 = 48 and 17 Ã 4 = 68
=
48 ....12
----- = ----
68 ,,,, 17
=
Î = 8
----