I am really struggling on my pre-cal homework, and I would just like a walk through of how to do this.
Update:**f(x) = √(3-x)** is the problem (sorry guys!) and I am trying to find the domain and range
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Verified answer
f(x) = sqrt( 3 - x ) is defined when
3 - x >= 0, i.e., 3 >= x, i.e., x <= 3.
Hence, Domain = ( -infinity, 3 ].
Then, sqrt of a non-negative real is a non-negative
real, i.e., f(x) is >= 0.
Hence, Range = [ 0, +infinity ).
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Happy To Help !
You haven't presented a "problem" yet. All you have done is present an equation. Do you want to find the derivative? What, EXACTLY, are you being asked to do with this equation?
You need to use parentheses, otherwise it's hard to tell if you mean
f(x) = √(3-x)
or
f(x) = (√3) - x
Assuming you need to graph the functions:
http://www.flickr.com/photos/dwread/3950344299/