(54.7 x 10^3 g H2) / (2.01588 g H2/mol) x (1 mol CH3OH / 2 mol H2) x (32.0419 g CH3OH/mol) =
434721 g = 435000 g CH3OH
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
(54.7 x 10^3 g H2) / (2.01588 g H2/mol) x (1 mol CH3OH / 2 mol H2) x (32.0419 g CH3OH/mol) =
434721 g = 435000 g CH3OH