factor it...
f(x) = 100x^2 + 80x + 16 = 4[25x^2 + 20x + 4] = 4(5x + 2)^2.
100x² + 80x + 16 = 4 ( 25x^2 + 20x +4)
= 4 (5x+2)^2
100x² + 80x + 16
4(25x² + 20x + 4)
= 4(5x + 2)^2
100x^2 + 80x + 16
=4(25x^2 +20x +4)
=4{25x^2+(10+10)x+4}
=4(25x^2+10x+10x+4)
=4{5x(5x+2)+2(5x+2}
=4(5x+2)(5x+2)
=4(5x+2)^2
Next method,
=(10x)^2 + 2.10x.4 +4^2
=(10x +4)^2 (since (a+b)^2 = a^2 + 2ab + b^2)
=(2(5x+2))^2
(10x + 4)²
(10x+4)^2
(10x + 4)(10x+ 4)
4(5x + 2)(5x + 2)
x
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Answers & Comments
f(x) = 100x^2 + 80x + 16 = 4[25x^2 + 20x + 4] = 4(5x + 2)^2.
100x² + 80x + 16 = 4 ( 25x^2 + 20x +4)
= 4 (5x+2)^2
100x² + 80x + 16
4(25x² + 20x + 4)
= 4(5x + 2)^2
100x^2 + 80x + 16
=4(25x^2 +20x +4)
=4{25x^2+(10+10)x+4}
=4(25x^2+10x+10x+4)
=4{5x(5x+2)+2(5x+2}
=4(5x+2)(5x+2)
=4(5x+2)^2
Next method,
100x^2 + 80x + 16
=(10x)^2 + 2.10x.4 +4^2
=(10x +4)^2 (since (a+b)^2 = a^2 + 2ab + b^2)
=(2(5x+2))^2
=4(5x+2)^2
(10x + 4)²
(10x+4)^2
100x² + 80x + 16
= 4(5x + 2)^2
(10x + 4)(10x+ 4)
4(25x² + 20x + 4)
4(5x + 2)(5x + 2)
x