How do you integrate: ∫sinx(lnx)dx?
Answer is:
(1/2)(xsin(lnx) - xcos(lnx)) + c
Update:I didn't write anything wrong but I was assuming my teacher might've wrote it wrong so I was asking to see what other people got.
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Do you feel like writing your question correctly?
She mean (uv)' = u'v + v'u. Here is u and u'. Don't forget dx as v.