How do you calculate the limit of 2/(√(2*x+2Δx +1)+√(2*x+1)) as Δx->0?
Update:
Thank you for your answer Wen Tian Qian. Could you please explain how you got 2/[2√(2x + 1)] from the limit of 2/(√(2*x+2Δx +1)+√(2*x+1)) as Δx->0?
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It is just 2/[2√(2x + 1)] = 1/√(2x + 1)
You got it right with finding derivative of √(2x + 1) by first principle : )