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There would be two real number solutions. There would be three answers, but one of those answers would be imaginary; therefore, there are 2 real number solutions.
No need to approximate the zeros of this function, since it's easily factorable to:
f(x) = (x - 3)(x - 2)(x + 1) --> It has zeros at x = 3, 2, and -1.
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There would be two real number solutions. There would be three answers, but one of those answers would be imaginary; therefore, there are 2 real number solutions.
No need to approximate the zeros of this function, since it's easily factorable to:
f(x) = (x - 3)(x - 2)(x + 1) --> It has zeros at x = 3, 2, and -1.