P(x)=0.04x^2+8

P(2)=0.04(2)^2+8

P(2) = 8.16 million

The rate of change of profit is given by the slope, m. For every year that the company operates its business, its annual profits will increase at a rate of 0.04.

I DON'T KNOW ECONOMICS BUT THE RATE OF CHANGE MAY REQUIRE FIRST DERIVATIVE.

.P(x)=0.04x^2+8

=>P'(x)=2*(0.04)x+0

=>P'(x)=0.08x.

So, after two years P'(2)=0.08*2(million)=0.16million.

P(x) = (x/5)^2 + 8

P ' (x) = 2(x/5)(1/5) = 2x/25

evaluate P '(2) = 4/25 = (2/5)^2 = 16/100 = 0.16 = 16%