How do I solve ³√4 divided by √2?
I put them into 4^(1/3) over 2^(1/2) and then found a common denominator such that
4^(2/6) over 2^(3/6)
.... now wut?
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I put them into 4^(1/3) over 2^(1/2) and then found a common denominator such that
4^(2/6) over 2^(3/6)
.... now wut?
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Verified answer
change the 4 to 2^2
(2^2)^2/6 = 2^(4/6)
Now you have 2^(4/6)/2^(3/6)
I get 2^(1/6)
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