The force required to stretch a Hooke’s-law spring varies from 0 N to 48.8 N as we stretch the spring by movin?
The force required to stretch a Hooke’s-law
spring varies from 0 N to 48.8 N as we stretch
the spring by moving one end 8.46 cm from
its unstressed position.
Find the force constant of the spring.
Answer in units of N/m
NOW
Find the work done in stretching the spring.
Answer in units of J
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Verified answer
F = K*X, F = 48.8 N, X =.846m so K = 48.8/.846 = 58.7 N/m....for finding work use W = (1/2 )*k*x^2