Find the position of the centre of mass of the framework which is formed by bending a uniform piece of wire of total length (12+2pi)cm to form a sector of a circle,centre O, radius 6cm.
Please explain this
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If the radius is 6 cm, the circumference is 12π = 37.70 cm
the wire is 18.28 cm long, so it's a bit less than half a circle.
Assuming the diameter of the wire is small compared to the other dimensions.
from reference
Uniform Sector:- centre of mass is on the axis of symmetry at a distance
d = (2Rsinθ) / 3θ
from the centre, where θ is measured in radians and is half the total angle of the arc.