I know theres an identity where you put a constant in the front, but I dont remember if it was when its cos²x or cosx² or something else...?
Update:Well, I am trying to find the derivative of cos²x, as dan said...is the derivative of cos²x, 2cosx?
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cos²x = 2cosx if and only if cosx = 0 so that is not an identity.
Perhaps you are thinking of the double angle identity:
sin(2x) = 2sin(x)cos(x)
or
cos(2x) = cos²x - sin²x = 2cos²x - 1 = 1 - 2sin²x
it's cos²x
If cos(x)cos(x) = 2cos(x) then cos(x) = 2 which is not true obviously, cos(x) is never 2.
cos²x does not equal 2cosx
you confuse it with the derivative of cos²x, which is 2cos x if I'm correct
EDIT: whoops, my bad. the derivative of cos²x isn't 2cos x. sorry.
No! If cos(x)cos(x) = 2cos(x)
then cos(x) = 2, which is clearly not true.
No.