You have corrected the problem to root4 root7+root4 root7.Actually only similiar surds can be added or subtracted.The rule is that you must take the common first. the process should be root 4 root7(1+1) =2 root 4 root 7 .you can write the answer as 2* 4^ (1/2)*7^(1/2) or as 2* 4 radical 7 radical.Sorry, no root sign is there in my keyboard.
it becomes 8â7. just imagine the 'â7' is 'x'. you obviously can't add x, you just add the coefficient. it's the same case here, so you just add 4 + 4.
i think u should ask google or yahoo not us cuz damn i noe i cant answer dat or ask google or yahoo for a math helper becasue iv done that b4 and it helps but i forgot wich 1 i used if not i wouldv given it 2 u sorry
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You have corrected the problem to root4 root7+root4 root7.Actually only similiar surds can be added or subtracted.The rule is that you must take the common first. the process should be root 4 root7(1+1) =2 root 4 root 7 .you can write the answer as 2* 4^ (1/2)*7^(1/2) or as 2* 4 radical 7 radical.Sorry, no root sign is there in my keyboard.
Well first of all, the SQRT(4) = 2.
So, basically, you have....
2(SQRT(7)) + 2(SQRT(7))
With this type of problem, you add the numbers and not the square (treat the square root like a variable).
2(SQRT(7)) + 2(SQRT(7)) = 4(SQRT(7))
it becomes 8â7. just imagine the 'â7' is 'x'. you obviously can't add x, you just add the coefficient. it's the same case here, so you just add 4 + 4.
i think u should ask google or yahoo not us cuz damn i noe i cant answer dat or ask google or yahoo for a math helper becasue iv done that b4 and it helps but i forgot wich 1 i used if not i wouldv given it 2 u sorry