i have two questions below :
1. a sharpshooter hits a target with probability 0.75. assuming independence, find the probabilities of getting 1) a hit followed by two misses? 2) two hits and a miss in any order?
2. a coin is loaded so that the probabilities of heads and tails are 0.52 and 0.48, respectively, if the coin is tossed three times, what are the probabilities of getting 1) all heads? 2) two tails and a head in that order?
please step by step
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Verified answer
1(1) P(a hit followed by two misses)
= 0.75 * 0.25 * 0.25
= 0.046875
1(2) P(two hits and a miss in any order)
=C(3,2)(0.75)^2(0.25)
= 0.421875
2(1) P(all heads) = 0.52^3 = 0.140608
2(2) P(two tails and a head in that order)
= 0.48 * 0.48 * 0.52
= 0.119808