因為cdf:f(x)為不連續函數，表示機率分配有點機率，因此P(x=1)=f(1)-f(x<1)=1/3-0=1/3P(x=4)=f(4)-f(1≦x<4)=1/2-1/3=1/6P(x=6)=f(6)-f(4≦x<6)=5/6-1/2==1/3P(x=10)=f(10)-f(6≦x<10)=1-5/6=1/6a． p(2<x≦6)= P(x=4)+ P(x=6)=1/6+1/3=1/2b．P(x=4)=1/6c． the probability distribution of x：g(x)=1/3 for x=1 =1/6 for x=4 =1/3 for x=6 =1/6 for x=10 =0 else
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因為cdf:f(x)為不連續函數，表示機率分配有點機率，因此P(x=1)=f(1)-f(x<1)=1/3-0=1/3P(x=4)=f(4)-f(1≦x<4)=1/2-1/3=1/6P(x=6)=f(6)-f(4≦x<6)=5/6-1/2==1/3P(x=10)=f(10)-f(6≦x<10)=1-5/6=1/6a． p(2<x≦6)= P(x=4)+ P(x=6)=1/6+1/3=1/2b．P(x=4)=1/6c． the probability distribution of x：g(x)=1/3 for x=1 =1/6 for x=4 =1/3 for x=6 =1/6 for x=10 =0 else