sorry I forgot the rest of the question,
a) f(-1)
x=0, y=-3
x=1, y=1
x=2, y=5
x=3, y=9
etc
Plot these points on, and draw a straight line through them.
Teh easy point to graph is (0, -3). From then on, just chose points for x, such as -2, -1, 0, 1, 2 and find their values and plot the points.
here is a table
x=1 f(1)= 4(1)-3=1 therefore, when x=1, y=1
x=2 f(2)= 4(2)-3=5 when x=2, y=5
x=0 f(0)= 4(0)-3=-3 when x=0, y= -3
get it?
it is already in the form y = mx + b
where
m = slope = 4
b = y intercept = -3
so start at the point (0,-3) go up 4, and over 1, in the direction so the graph has a positive slope.
It's just a line with a slope of 4 and a y-intercept of -3. Draw a line through the points (0,-3) and (1,1).
Easy.
Copyright © 2024 1QUIZZ.COM - All rights reserved.
Answers & Comments
Verified answer
x=0, y=-3
x=1, y=1
x=2, y=5
x=3, y=9
etc
Plot these points on, and draw a straight line through them.
Teh easy point to graph is (0, -3). From then on, just chose points for x, such as -2, -1, 0, 1, 2 and find their values and plot the points.
here is a table
x=1 f(1)= 4(1)-3=1 therefore, when x=1, y=1
x=2 f(2)= 4(2)-3=5 when x=2, y=5
x=0 f(0)= 4(0)-3=-3 when x=0, y= -3
get it?
it is already in the form y = mx + b
where
m = slope = 4
b = y intercept = -3
so start at the point (0,-3) go up 4, and over 1, in the direction so the graph has a positive slope.
It's just a line with a slope of 4 and a y-intercept of -3. Draw a line through the points (0,-3) and (1,1).
Easy.