Okay, not sure what you mean by an intro to fractions. If you typed it right, this is just what I call a plug and chug problem. For all a, b, and c, you simply put the number thats in the parenthesis everywhere you see x in the equation. Therefore just use your calculator. If you don't have one, heres the answers:
it is f(10) so x might desire to correspond to 10 interior the ordered pairs (ie the 1st one) f(10) = 10² - 7*10 + 9 (replace x with 10) f(10) = one hundred - 70 + 9 = 39 so the ordered pair is: (10,39)
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Verified answer
for every x, substitute the number in the parenthesis:
f(x) = x^2 – 7x + 10
a.
f(0) = 0^2 - 7(0) + 10
f(0) = 0 - 0 + 10
f(0) = 10
b.
f(5) = 5^2 - 7(5) + 10
f(5) = 25 - 35 + 10
f(5) = 0
c.
f(-2) = (-2)^2 - 7(-2) + 10
f(-2) = 4 + 14 + 10
f(-2) = 28
Okay, not sure what you mean by an intro to fractions. If you typed it right, this is just what I call a plug and chug problem. For all a, b, and c, you simply put the number thats in the parenthesis everywhere you see x in the equation. Therefore just use your calculator. If you don't have one, heres the answers:
a)f(0) = 0(2 )– 7(0) + 10=10
b)f(5) = (5)2 – 7(5) + 10= -15
c) f(-2) = (-2)2 – 7(-2) + 10=20
f(0) = 0^2 - 0 + 10 = 10
f(5) = 5^2 - 35 + 10 = 0
f(-2) = 4 + 14 + 10 = 28.
I cannot see what this has to do with fractions.
Some people have taken x2 to mean 2x, and others have taken it to mean x^2 (x squared). That's why you are getting inconsistent answers.
if that is an x squared term
all that you do..
for (A) substitute 0 for every x you see, so 0^2 - 7(0) + 10 = 10
(B) 5^2 - 7(5) +10
= 25 - 35 + 10
=0
(C) (-2)^2 - 7(-2) + 10
= 4 + 14+ 10 = 28
it is f(10) so x might desire to correspond to 10 interior the ordered pairs (ie the 1st one) f(10) = 10² - 7*10 + 9 (replace x with 10) f(10) = one hundred - 70 + 9 = 39 so the ordered pair is: (10,39)
a) 10
b) -15
c) 20
a) -10
b) -15
c) 34