Start by making a point at (0, -5), which is the y-intercept (b). Then plug in two values for x on opposite sides of y = 0. For instance, -2 will yield -1, and 2 will yield -9. Last, connect points (-2, -1) and (2, -9), which will intersect (0, -5) along the way. Finished.
Do you relatively think of all of us is going to respond to all of those questions for you? This sounds like an examination, or consistent with probability an examination overview. that's advisable to reassess being a math significant!
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Verified answer
This is the equation of a line.
Put x=0. Then
f(0) = -2·0 – 5 = 0 - 5 = -5
=> the line goes through the point (0, -5)
Put x=1. Then
f(1) = -2·1 – 5 = -2 - 5 = -7
=> the line goes through the point (1, -7)
Plot the points (0, -5) and (1, -7) in the coordinate system and draw a straight line through them!
If you want, you can calculate more points:
f(-3) = -2·(-3) – 5 = 6 - 5 = 1
=> point (-3, 1)
f(-4) = -2·(-4) – 5 = 8 - 5 = 3
=> point (-4, 3)
etc.
All these points are on the line!
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Hope this helps.
Start by making a point at (0, -5), which is the y-intercept (b). Then plug in two values for x on opposite sides of y = 0. For instance, -2 will yield -1, and 2 will yield -9. Last, connect points (-2, -1) and (2, -9), which will intersect (0, -5) along the way. Finished.
A straight line.
When x = 0, f(x) = -5
When f(x) = 0,
0 = -2x - 5
2x = -5
x = -5/2
So the line passes through points (0, -5) and (-5/2, 0) on the y and x axes respectively.
Do you relatively think of all of us is going to respond to all of those questions for you? This sounds like an examination, or consistent with probability an examination overview. that's advisable to reassess being a math significant!
start at (0,-5) and go down 2 squares to the right 1 square. repeat
slope=-2/1 y-intercept (0,-5) x-intercept (-2.5,0)
Plot two points and draw line with ruler
you need a pencil, paper, and a calculator to figure that out, its a liner equation and cannot be shown on a text editor.
um..I think thats a line equation.