For the reaction ? C6 H6 + ? O2 → ? CO2 + ? H2 O ...?
373 grams of CHare allowed to react with 101 grams of O2 . How much CO2 will be produced by this reaction in grams?
Update:37.3g of C6H6 reacts with 101g of O2, how much CO2 is created by this reaction, in grams please?
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2 C6H6 +15 O2 = 12 CO2 + 6 H2O
moles C6H6 = 373 /78.114 g/mol= 4.78
moles O2 = 101/32=3.16
moles O2 needed = 4.78 x 15/2=35.9
O2 = limiting reactant
Moles CO2 = 3.16 x 12/15=2.53
mass CO2 = 2.53 x 44 g/mol=111 g