To solve for the x-intercept, you'll plug in 0 for y and solve. This makes sense because for x-intercepts, the ordered pair (x,y) y has to be zero because it crosses the x-axis.
0=-x-9
9= -x
-9=x
To solve for the y-intercept, you'll plug in 0 for x and solve. This makes sense because in y-intercepts, when you're looking at the graph, the x has to be zero in order for it to cross the y-axis.
the y-int is "b" in that format, so the y-int would be "-9".
if you substitute in "0" for y in the equation, you will get the x-int (because wherever the line crosses the x axis the y value will be zero). therefore...
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To solve for the x-intercept, you'll plug in 0 for y and solve. This makes sense because for x-intercepts, the ordered pair (x,y) y has to be zero because it crosses the x-axis.
0=-x-9
9= -x
-9=x
To solve for the y-intercept, you'll plug in 0 for x and solve. This makes sense because in y-intercepts, when you're looking at the graph, the x has to be zero in order for it to cross the y-axis.
y= -0 -9
y=-9
ok. y = mx + b
the y-int is "b" in that format, so the y-int would be "-9".
if you substitute in "0" for y in the equation, you will get the x-int (because wherever the line crosses the x axis the y value will be zero). therefore...
y = -x - 9
0 = -x - 9
*add 9*
9 = -x
*divide by -1*
-9 = x
...so the x-int is -9, also.
hope i was able to help. :)
imagine x=0 because at the y intercept, the x coordinate is zero
then
y= -(0) - 9
y=-9
the y intercept is -9