A) 3x + y = –7
B) 3x + y = –1
C)3x + y = –5
D) 3x + y = 5
Update:Find the standard form for the equation of the line which passes through the point (–1, –2) and is parallel to the line that has an equation of 6x + 2y = 4.
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Verified answer
write the equation in slope-intercept form y = mx + c, m is slope and c is y-intercept.
y = -3x + 2
slope = -3
parallel lines has same slope, so the line equation is y = -3x + c
Substitute (–1, –2) to find the y-intercept value
-2 = -3 * -1 + c
c = -5
The line equation is y = -3x -5
The line equation in standard form is 3x + y = -5
Option C is right choice.
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Parallel lines have comparable slope 6x+2y=4. remedy this for y to get. Y= -3x+2 The slope is -3. ( its continuously the # in front of x) utilising y= mx+ b, plug -a million into x, -3 as m , and -2 as y and remedy for b . -2=-3(-a million)+b -2=3+b B=-5 So eq would be. Y=-3x-5
For this problem, the easiest thing to do is to plug in the point given into the equations given and find which gives the correct answer.
3x + y = ?
3(-1) + (-2) = ?
-3 - 2 = ?
-5 = -5
So our answer is C.
Hope this helps.