Verified answer

let 2x-(π/3) be limited to the 2π period

0 ≤ 2x-(π/3) ≤ 2π ====> adding π/3

π/3 ≤ 2x ≤ 7π/3

π/6 ≤ x ≤ 7π/6 =====> now we have 2 points .....the other 3 are as following:

[ π/6 + 7π/6 ] / 2 = 8π/12 = 2π/3

[ π/6 + 2π/3 ] / 2 = 5π/12

[ 7π/3 + 2π/3 ] / 2 = 9π/6 = 3π/2

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