The summation from 0 to +infinity. If that wasn't clear.
By the Ratio Test, it converges for |x| < ½.
You consider the ratio | [(n+1)² 2^(n+1) x^(n+1)]/[n² 2^n x^n] | as n→∞ and determine the values of x for which this is less than 1.
The ratio simplifies to [((n+1)/n)²] * 2|x|
As n→∞ ((n+1)/n)² →1 so the series converges when 2|x| < 1, that is, for |x| < ½.
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Answers & Comments
By the Ratio Test, it converges for |x| < ½.
You consider the ratio | [(n+1)² 2^(n+1) x^(n+1)]/[n² 2^n x^n] | as n→∞ and determine the values of x for which this is less than 1.
The ratio simplifies to [((n+1)/n)²] * 2|x|
As n→∞ ((n+1)/n)² →1 so the series converges when 2|x| < 1, that is, for |x| < ½.