Verified answer

Well, let's find the y intercept(s) first, they're easier.

Make x = 0, so

y^4 = 0

y = +/- 0 (So just 0)

Now let's make y = 0:

x(x^2 - 9) = 0

x = -3, 0, 3

Have a great day!! :-)

intercepts

when x=0, y=0

when y=0......

x^3-9x

x(x^2-9)

x(x+3)(x-3)

.....= 0, +/-3

intercepts

(-3,0),(0,0),(3,0)