a + 2b = [4, -1] which has magnitude √(4² + 1²) = √17.
So in order to scale this vector down to a unit, you must divide by +/-√17. This can be positive or negative (1 and -1 are the units in the ring of real numbers).
So, you want answer 3.
Or directly, in a few lines:
λ(a+2b) is unit vector <=> magnitude of λ([4,-1]) = 1
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Verified answer
a + 2b = [4, -1] which has magnitude √(4² + 1²) = √17.
So in order to scale this vector down to a unit, you must divide by +/-√17. This can be positive or negative (1 and -1 are the units in the ring of real numbers).
So, you want answer 3.
Or directly, in a few lines:
λ(a+2b) is unit vector <=> magnitude of λ([4,-1]) = 1
<=> magnitude of [4λ,-λ] = 1
<=> 4²λ²+(-1)²λ² = 1
<=> 17λ² = 1
<=> λ² = 1/17
<=> λ = +/- 1/√17