Verified answer

[ 8y - (8/27) y³ ] -------------limits - 3 to 3

[ 24 - 8 ] - [ - 24 + 8 ] = 48 - 16 = 32

Evaluate ∫[-3,3] {8 - (8/9)y²}dy?

∫[-3,3] {8 - (8/9)y²}dy = [8y -(8/9)y^3/3][-3,3] =

= [8(-3) -(8/9)(-3)^3/3] - [8(3) -(8/9)(3^3)/3] =

= -24 +8 -(24 - 8) = -32 >==================< ANSWER

8y - (8/27)y^3 [-3,3]

Plug in 3 for y to get

8(3) - (8/27)*3^3 = 16

Plus in -3 for y to get

8(-3) - (8/27)*-3^3 = -16

Add those two together and you get 0