∫ [(e^2x + 1)/(e^2x - 1)] dx =?
possible book solutions....
a. (1/4)ln (1 + 2e^2x) + C
b. -(1/4)ln |1 - 2e^2x | + C
c. -(1/2)ln |2 - e^2x| + C
d. (1/2)ln (2 + e^2x) + C
e. ln| e^x – e^-x| + C
f. ln| e^x + e^-x| + C
g. x – e^-2x + C
h. x + e^2x + C
i. none of these
More Questions From This User See All
Answers & Comments
Verified answer
------- i --------
Its e^2*x + C. I went to http://integrals.wolfram.com/index.jsp and it solves any integral for u.
i. none of these