Verified answer

dy/dx=5/3x^(-2/3)-21x^2+2

Simply take the derivative of each of the terms individually.

f(x) = 5∛x - 7x^3 + 2x - 6 = 5x^(1/3) - 7x^3 + 2x - 6

ergo dy/dx = f'(x) = (5/3)x^(-2/3) - 21x^2 + 2

y=5*x^(1/3)-7x^3 + 2x -6

y=5/3*x^(-2/3)-21x^2 + 2