números complexos
z² = 51 + 140i
51 + 140i = 100 + 140i - 49 = 100 + 140i + (7i)² = (10 + 7i)²
51 + 140i = 100 + 140i - 49 = 100 + 140i + (-7i)² = (10 - 7i)²
z1 = 10 + 7i
z2 = 10 - 7i
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Verified answer
z² = 51 + 140i
51 + 140i = 100 + 140i - 49 = 100 + 140i + (7i)² = (10 + 7i)²
51 + 140i = 100 + 140i - 49 = 100 + 140i + (-7i)² = (10 - 7i)²
z1 = 10 + 7i
z2 = 10 - 7i
pronto