f (9 ¹/²) , f (- 3/4) e f (raiz quadrada de 5 / 2)
me ajude por favor. ' é valendo ponto pra prova. muito obrigada.
f(x)=4x+9
f(9^1/2)=4x+9
f(√9)=4x+9
f(3)=4.3+9
f(3)=12+9=21 >>>
f(-3/4)=4.(-3/4)+9
f(-3/4)=-12/4 + 9
f(-3/4)=-3+9= 6 >>>
f(√5/2)=4.√5/2 + 9
f(√5/2)=2√5 + 9 >>>>
f(x) = 4x + 9
f(9¹/²) = 4.9¹/² + 9 = 4.√9 + 4 = 4.3 + 4 = 16
f(-3/4) = 4.(-3/4) + 9 = -3 + 9 = 6
f(√5/2) = 4.√5/2 + 9 = 2√5 + 9
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Verified answer
f(x)=4x+9
f(9^1/2)=4x+9
f(√9)=4x+9
f(3)=4.3+9
f(3)=12+9=21 >>>
f(x)=4x+9
f(-3/4)=4.(-3/4)+9
f(-3/4)=-12/4 + 9
f(-3/4)=-3+9= 6 >>>
f(x)=4x+9
f(√5/2)=4.√5/2 + 9
f(√5/2)=2√5 + 9 >>>>
f(x) = 4x + 9
f(9¹/²) = 4.9¹/² + 9 = 4.√9 + 4 = 4.3 + 4 = 16
f(-3/4) = 4.(-3/4) + 9 = -3 + 9 = 6
f(√5/2) = 4.√5/2 + 9 = 2√5 + 9