how do i solve this?
I think the format is wrong... its the square root sign and in it is 15×20×12
first you start off by multiplying out everything under the square root sign
so 15x20x12=3600
then you take the square root of 3600 which is 60
so thats your answer
so you need to find factors that are perfect squares. 15 doesn't have any
but 20 has 4 and 12 also has 4
so when you factor out of a square root you must actually take the square root (ALWAYS positive one)
so â 15*20*12 = â 15*4*5*4*3 = â 3*5*4*5*4*3 = â 9*25*16 = 3*5*4 = 60
â (15*20*12)
From here lets factor all of our numbers
â (15*20*12) = â (3*5*2*2*5*3*2*2) = â (2*2*2*2*3*3*5*5)
We can take each pair and pull them out of the square root, like â (2*2) = 2
so
â (2*2*2*2*3*3*5*5) = 2*2*3*5 = 60
â(15*20*12)=
=â(3*5*5*4*3*4)=
=3*5*2*2=15*4=60
â(15 * 20 * 12)
â(3*5 * 4*5 * 3*4)
â(3*3 * 4*4 * 5*5)
â(3² * 4² * 5²)
3 * 4 * 5
60
sqrt( 15*20*12)= sqrt(3*5*2*2*5*2*2*3)
= sqrt( 2*2 *2*2 *3*3 *5*5)
= sqrt(2*2) * sqrt (2*2) * sqrt (3*3) * sqrt (5*5)
= 2 * 2 * 3 * 5 = 60
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Answers & Comments
Verified answer
first you start off by multiplying out everything under the square root sign
so 15x20x12=3600
then you take the square root of 3600 which is 60
so thats your answer
so you need to find factors that are perfect squares. 15 doesn't have any
but 20 has 4 and 12 also has 4
so when you factor out of a square root you must actually take the square root (ALWAYS positive one)
so â 15*20*12 = â 15*4*5*4*3 = â 3*5*4*5*4*3 = â 9*25*16 = 3*5*4 = 60
â (15*20*12)
From here lets factor all of our numbers
â (15*20*12) = â (3*5*2*2*5*3*2*2) = â (2*2*2*2*3*3*5*5)
We can take each pair and pull them out of the square root, like â (2*2) = 2
so
â (2*2*2*2*3*3*5*5) = 2*2*3*5 = 60
â(15*20*12)=
=â(3*5*5*4*3*4)=
=3*5*2*2=15*4=60
â(15 * 20 * 12)
â(3*5 * 4*5 * 3*4)
â(3*3 * 4*4 * 5*5)
â(3² * 4² * 5²)
3 * 4 * 5
60
sqrt( 15*20*12)= sqrt(3*5*2*2*5*2*2*3)
= sqrt( 2*2 *2*2 *3*3 *5*5)
= sqrt(2*2) * sqrt (2*2) * sqrt (3*3) * sqrt (5*5)
= 2 * 2 * 3 * 5 = 60