need help please
The formula is fairly simple:
Q (heat) = Cp (Specific Heat) × mass × (d)T (temp change)
You need the Cp for water: 1 cal/gram°C or 4.186kJoules/kg°C
Assuming your truncated question is 40.5C to 100C,
here's an example:
Q = Cp × m × (d)T
Q = 4.186kJ/kgC × .224kg × (100C-40.5C) = 55.8 kJoules
or
Q = 1cal/gC × 224g × 59.5C = 13,328 calories
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The formula is fairly simple:
Q (heat) = Cp (Specific Heat) × mass × (d)T (temp change)
You need the Cp for water: 1 cal/gram°C or 4.186kJoules/kg°C
Assuming your truncated question is 40.5C to 100C,
here's an example:
Q = Cp × m × (d)T
Q = 4.186kJ/kgC × .224kg × (100C-40.5C) = 55.8 kJoules
or
Q = 1cal/gC × 224g × 59.5C = 13,328 calories