By Chebyshev's Theorem, at least how many students in a class of 200 would score within the range μ 2σ ?
By the Empirical Rule, how many students in a class of 200 would score within the range μ 2σ ? (Round your answer to the nearest whole number.)
How do i solve this problem? i know the Chebychev Theorem is 1-1/k^2
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ANSWER: A minimum of 150 students of a class of 200 score with the range μ +/- 2σ
Why??
Chebyshev's inequality states that not more than 1/k² of the distribution's values can be more than k standard deviations away from the mean. And for this problem, k = 2 which means that not less than 75% [(1 - 1/2²)*100] of the values are within k = 2 standard deviations of the mean = μ.
(0.75)*(200) = 150 minumum