I have delta h=-777kj+1atmospheres× delta V. I just dont know how to find delta V from the problem.
The reaction is:
2 C2H6 + 7 O2 → 4 CO2 + 6 H2O
So you need the heat produced by the complete combustion of 2 moles of C2H6.
(15.0 g C2H6) / (30.06924 g C2H6/mol) = 0.49885 mol C2H6
(777 kJ) / (0.49885 mol) x (2 mol) = 3115 kJ
So:
2 C2H6 + 7 O2 → 4 CO2 + 6 H2O, ΔH = 3115 kJ
The answer is -3120 kJ
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The reaction is:
2 C2H6 + 7 O2 → 4 CO2 + 6 H2O
So you need the heat produced by the complete combustion of 2 moles of C2H6.
(15.0 g C2H6) / (30.06924 g C2H6/mol) = 0.49885 mol C2H6
(777 kJ) / (0.49885 mol) x (2 mol) = 3115 kJ
So:
2 C2H6 + 7 O2 → 4 CO2 + 6 H2O, ΔH = 3115 kJ
The answer is -3120 kJ