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A gas has a pressure of 0.370 atm at 50.0 °C. What is the pressure at standard temperature?
What is the volume of gas at 2.00 atm and 200.0 K if its original volume was 300.0 L at 0.250 atm and 400.0 K?
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Verified answer
0.370/ 323 = p/273
p = 0.313 atm
300 x 0.250/400= V x 2.00/ 200
V = 18.8 L