Verified answer

Neglecting air resistance, the time to peak altitude is the same as the time from peak altitude. Therefore the time to peak altitude is 6 seconds. Peak altitude occurs when the projectile's vertical velocity slows to a stop just before falling at acceleration g.

We can write:

Vy(6) = 0 = Vyo -9.8*6 => Vyo = 58.8m/s

Vyo = Vo*sin35 => Vo = 102.5 at 35 degrees. a) <-----------------------

Now that we have Vyo, we can calculate the peak altitude h

h = 58.8*6 - 4.9*36 = 176.4m b) <------------------------------

That means it takes 6 seconds going up and 6 going down.

How high would you drop a rock from to have it take 6 seconds to land?

d = ½gt² = 176.4 meters (b)

v = √(2gh) = 58.8 m/s

this is the vertical component of the overall velocity, which is equal to V sin θ

58.8 = V sin 35

V = 102.5 m/s