A grandfather clock is controlled by a swinging brass pendulum that is 1.4 m long at a temperature of 27°C.
(a) What is the length of the pendulum rod when the temperature drops to 0.0°C?
m
(b) If a pendulum's period is given by T = 2(L/g), where L is its length, does the change in length of the rod cause the clock to run fast or slow?
fast
neither
slow
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Verified answer
Linear expansion/contraction of brass = 18.9 x 10/1,000,000/°C
a.)..Length at 27°C = 1.4 m
At 0°C = 27°C drop.
18.9 x (10,/1,000,000) x 27 = 0.0005103 m
New length = 1.4 - 0.0005103 = 1.3995 m
b.)..As the change makes the pendulum shorter, the swing is shorter .. the clock runs faster.