heated. At what temperature will it burst?
____________C°
From ideal gas law
P∙V = n∙R∙T
follows
P/T = n∙R/V constant
because neither the amount of gas enclosed in the flask nor the flask volume changes.
Actually the will be a slight change of the volume due to thermal expansion of the flask, but you can ignore that effect for this problem
Hence,
P_final/T_final = P_initial/T:_initial
Thus the temperature at which the gas in the flask has reached a certain pressure is given by:#
T_final = T_initial ∙ (P_final / P_initial)
Initial pressure is not given. So let's assume that the flask was filled with gas at standard atmospheric pressure, i.e.
P_initial = 1 atm = 760 torr
Then the gas will reach the critical pressure at a temperature of
T_final = (21 + 273) K ∙ (2508 torr / 760 torr )
= (21 + 273) K ∙ (2508 torr / 760 torr )
= 970 K
= 697 °C
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Verified answer
From ideal gas law
P∙V = n∙R∙T
follows
P/T = n∙R/V constant
because neither the amount of gas enclosed in the flask nor the flask volume changes.
Actually the will be a slight change of the volume due to thermal expansion of the flask, but you can ignore that effect for this problem
Hence,
P_final/T_final = P_initial/T:_initial
Thus the temperature at which the gas in the flask has reached a certain pressure is given by:#
T_final = T_initial ∙ (P_final / P_initial)
Initial pressure is not given. So let's assume that the flask was filled with gas at standard atmospheric pressure, i.e.
P_initial = 1 atm = 760 torr
Then the gas will reach the critical pressure at a temperature of
T_final = (21 + 273) K ∙ (2508 torr / 760 torr )
= (21 + 273) K ∙ (2508 torr / 760 torr )
= 970 K
= 697 °C