One form of the Arrhenius equation is given as:

ln (k2/k1) = - Ea/R (1/T2-1/T1)

Temperatures must be in Kelvin, Ea in J/mol and R = 8.314 J/molK. Substituting into this equation gives:

ln(k2/2.40X10^-2) = -(7.10X10^4 J/mol/8.314 J/molK) (1/337 - 1/292)

ln(k2/2.40X10^-2) = 6.351

k2/2.40X10^-2 = 573

k2 = 13.7 s^-1

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